-2(t^2)-9t=0

Solution for -2(t^2)-9t=0 equation:

-2(t^2)-9t=0

a = -2; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·(-2)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*-2}=\frac{0}{-4}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*-2}=\frac{18}{-4}
=-4+1/2
$